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高频 SQL 50 题（基础版）_1667. 修复表中的名字
select user_id ,concat(upper(substring(name,1,1)),lower(substring(name,2))) as name
from Users
order by user_id
select user_id ,concat(upper(substring(name,1,1)),lower(substring(name,2))) as name
from Users
order by user_id